25v^2+60v+27=0

Solution for 25v^2+60v+27=0 equation:

25v^2+60v+27=0

a = 25; b = 60; c = +27;
Δ = b2-4ac
Δ = 602-4·25·27
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{900}=30$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-30}{2*25}=\frac{-90}{50}
=-1+4/5
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+30}{2*25}=\frac{-30}{50}
=-3/5
$